A) Hydrogen has little affinity to \[{{O}_{2}}\]
B) Hydrogen has more affinity to \[{{O}_{2}}\]
C) Hydrogen has more affinity to \[C{{l}_{2}}\]
D) It is a reducing agent
Correct Answer: C
Solution :
\[\underset{\text{Exposed to air}}{\mathop{{{H}_{2}}O+C{{l}_{2}}}}\,\,\to \,HCl+HClO\] \[HClO\,\to \,HCl+[O]\] or \[2HClO\,\to \,2HCl+{{O}_{2}}\]
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