A) 7
B) 6
C) \[-6\]
D) \[-7\]
Correct Answer: D
Solution :
Suppose that \[x\] to be added then numbers 13, 15, 19 so that new numbers \[x+13,\ 15+x,\ 19+x\] will be in H.P. \[\Rightarrow \]\[(15+x)=\frac{2(x+13)(19+x)}{x+13+x+19}\] \[\Rightarrow \]\[{{x}^{2}}+31x+240={{x}^{2}}+32x+247\Rightarrow x=-7\] Trick: Such type of questions should be checked with the options.You need to login to perform this action.
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