A) 1.73 : 1
B) 1 : 1.73
C) 1 : 1
D) 1 : 2
Correct Answer: B
Solution :
In first case \[{{\eta }_{1}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{(273+0)}{(273+200)}=\frac{200}{473}\] In second case \[{{\eta }_{2}}=1-\frac{(273-200)}{(273+0)}=\frac{200}{273}\] Þ \[\frac{{{\eta }_{1}}}{{{\eta }_{2}}}=\frac{1}{\left( \frac{473}{273} \right)}=1:1.73\]You need to login to perform this action.
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