A) 100W
B) 40W
C) 20W
D) 10W
Correct Answer: D
Solution :
\[P=\frac{{{V}^{2}}}{R}\] \[\Rightarrow \frac{{{P}_{2}}}{{{P}_{1}}}=\frac{V_{2}^{2}}{V_{1}^{2}}\] (\[\because R\] is constant) \[\Rightarrow \frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{100}{200} \right)}^{2}}=\frac{1}{4}\]\[\Rightarrow {{P}_{2}}=\frac{{{P}_{1}}}{4}=\frac{40}{4}=10\,W\]
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