JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Heating Effect of Current

  • question_answer
    An electric bulb is rated 60W, 220V. The resistance of its filament is                                          [MP PET 2003]

    A)            708 W                                      

    B)            870 W

    C)            807 W                                      

    D)            780 W

    Correct Answer: C

    Solution :

               \[R=\frac{{{V}^{2}}}{P}=\frac{{{(220)}^{2}}}{60}=807\,\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner