A) 1000 W
B) 750 W
C) 500 W
D) 250 W
Correct Answer: D
Solution :
\[\frac{{{P}_{1}}}{{{P}_{2}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{2}}\]\[\Rightarrow \frac{1000}{{{P}_{2}}}={{\left( \frac{220}{110} \right)}^{2}}=4\]Þ \[{{P}_{2}}=250\,W\]
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