A) 100 W
B) 40 W
C) 60 W
D) Equal in all bulbs
Correct Answer: A
Solution :
\[{{P}_{Rated}}=\frac{V_{Rated}^{2}}{R}\] Þ \[R\propto \frac{1}{{{P}_{Rated}}}\] (V - constant) So bulb of high power will have less resistance.
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