A) 0.1 W
B) 1 W
C) 10 W
D) 100 W
Correct Answer: B
Solution :
\[P=Vi\] Þ \[i=\frac{2.2\times {{10}^{3}}}{22000}=\frac{1}{10}A\] Now loss of power \[={{i}^{2}}R\]\[={{\left( \frac{1}{10} \right)}^{2}}\times 100\] = 1 W
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