A) 2 W
B) 6 W
C) 5 W
D) 4 W
Correct Answer: B
Solution :
\[P=\frac{{{V}^{2}}}{{{R}_{eq}}}\Rightarrow 150=\frac{{{(15)}^{2}}}{[2R/(R+2)]}=\frac{225\times (R+2)}{2R}\] Þ \[R=\frac{450}{75}=6\Omega \].You need to login to perform this action.
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