A) 10 watt
B) 30 watt
C) 10/3 watt
D) 90 watt
Correct Answer: D
Solution :
In series \[{{P}_{S}}=\frac{P}{n}\] Þ \[10=\frac{P}{3}\] Þ \[P=30\,W\] In parallel \[{{P}_{P}}=nP\] = 3 ´ 30 = 90 W
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