A) \[\frac{P}{3}\]
B) 3P
C) 9P
D) \[\frac{P}{9}\]
Correct Answer: C
Solution :
When bulbs are connected in series, \[P=\frac{{{V}^{2}}}{{{R}'}}=\frac{{{V}^{2}}}{3R}\] When bulbs are connected in parallel, \[{P}'=\frac{{{V}^{2}}}{{{R}''}}=\frac{{{V}^{2}}\times 3}{R}=3\times 3P=9P.\]
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