A) 50 watt
B) 75 watt
C) 90 watt
D) 25 watt
Correct Answer: D
Solution :
Resistance of the bulb = \[\frac{{{V}^{2}}}{{{P}_{Ratate}}}=\frac{220\times 220}{100}=484\Omega \] When connected with 110 V, the power consumed \[{{P}_{Consumed}}=\frac{{{V}^{2}}}{R}=\frac{110\times 110}{484}=25W\]
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