A) 2 : 1
B) 1 : 2
C) 4 : 1
D) 1 : 4
Correct Answer: D
Solution :
Power consumed means heat produced. For constant potential difference \[{{P}_{\text{consumed}}}=\text{Heat}\propto \frac{1}{{{R}_{eq}}}\] \[\therefore \frac{{{H}_{1}}}{{{H}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{R/2}{2R}=\frac{1}{4}\] (Since \[{{R}_{2}}=\frac{R.R}{R+R}=\frac{R}{2}\]and \[{{R}_{1}}=R+R=2R)\]
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