A) They have equal currents through them
B) The resistance of the filaments in both the bulbs is same
C) The resistance of the filament in 40 watt bulb is more than the resistance in 100 watt bulb
D) The resistance of the filament in 100 watt bulb is more than the resistance in 40 watt bulb
Correct Answer: C
Solution :
\[P=\frac{{{V}^{2}}}{R}\] \[\Rightarrow {{R}_{1}}=\frac{V_{1}^{2}}{{{P}_{1}}}=\frac{{{(200)}^{2}}}{40}=1000\Omega \] and \[{{R}_{2}}=\frac{V_{2}^{2}}{{{P}_{2}}}=\frac{{{(200)}^{2}}}{100}=400\Omega \]
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