A) 1.28 watt
B) 2.0 watt
C) \[\frac{8}{9}\,watt\]
D) 3.2 watt
Correct Answer: B
Solution :
\[{{P}_{\max }}=n\,\left( \frac{{{E}^{2}}}{4\,r} \right)=2\,\left( \frac{2\times 2}{4\times 1} \right)=2\,W\]
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