JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Heating Effect of Current

  • question_answer
    An electric bulb of 100 watt is connected to a supply of electricity of 220 V. Resistance of the filament is [EAMCET 1981, 82; MP PMT 1993, 97]

    A)            \[484\,\Omega \]               

    B)            \[100\,\Omega \]

    C)            \[22000\,\Omega \]          

    D)            \[242\,\Omega \]

    Correct Answer: A

    Solution :

               \[\frac{{{V}^{2}}}{R}=P\,\]Þ \[R=\frac{{{V}^{2}}}{P}=\frac{220\times 220}{100}=484\Omega \]


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