A) Resistances in the ratio of 4 : 1
B) Maximum current ratings in the ratio of \[1:4\]
C) Resistances in the ratio of 2 : 1
D) Maximum current ratings in the ratio of 1 : 2
Correct Answer: B
Solution :
\[R=\frac{{{V}^{2}}}{P}\] Þ \[{{R}_{1}}=\frac{200\times 200}{100}=400\,\Omega \] and \[{{R}_{2}}=\frac{100\times 100}{200}=50\,\Omega .\] Maximum current rating \[i=\frac{P}{V}\] So \[{{i}_{1}}=\frac{100}{200}\] and\[{{i}_{2}}=\frac{200}{100}\]Þ \[\frac{{{i}_{1}}}{{{i}_{2}}}=\frac{1}{4}\].
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