A) 2 : 1
B) 1 : 2
C) 1 : 4
D) 4 : 1
Correct Answer: A
Solution :
\[P=\frac{{{V}^{2}}}{R}\Rightarrow P\propto \frac{1}{R}\]and\[R\propto l\] \[\therefore P\propto \frac{1}{l}\Rightarrow \frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{2}{1}\]
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