A) \[7.2\times {{10}^{3}}\,J\]
B) \[14.4\times {{10}^{5}}\,J\]
C) \[43.2\times {{10}^{4}}\,J\]
D) \[28.8\times {{10}^{4}}J\]
Correct Answer: B
Solution :
\[H={{i}^{2}}Rt=\frac{{{V}^{2}}t}{R}=\frac{120\times 120\times (10\times 60)}{6}\]\[=14.4\times {{10}^{5}}joule\]
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