A) 0.16 J
B) 1.28 J
C) 0.64 J
D) 0.32 J
Correct Answer: D
Solution :
Heat produced = Energy stored in capacitor \[=\frac{1}{2}C{{V}^{2}}\]\[=\frac{1}{2}\times 4\times {{10}^{-6}}\times {{(400)}^{2}}\]\[=0.32\,\,J\]
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