JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Heating Effect of Current

  • question_answer
    A (100 W, 200 V) bulb is connected to a 160 V power supply. The power consumption would be [CBSE PMT 1997; JIPMER 2000]

    A)            64 W                                        

    B)            80 W

    C)            100 W                                      

    D)            125 W

    Correct Answer: A

    Solution :

               \[{{P}_{consumed}}={{\left( \frac{{{V}_{A}}}{{{V}_{R}}} \right)}^{2}}\times {{P}_{R}}=\frac{{{(160)}^{2}}}{{{(200)}^{2}}}\times 100\]\[=64\,\,W\]


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