A) 1210 W
B) 2000 W
C) 1000 W
D) None of these
Correct Answer: A
Solution :
\[P=\frac{{{V}^{2}}}{R}\Rightarrow R=\frac{{{V}^{2}}}{P}=\frac{{{(220)}^{2}}}{40}=1210\,\Omega \]
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