A) 16
B) 9
C) 6
D) 4
Correct Answer: B
Solution :
\[P=\frac{{{V}^{2}}}{R}\] Þ \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}\]Þ \[\frac{6}{{{P}_{2}}}=\frac{4}{6}=\frac{2}{3}\] Þ \[{{P}_{2}}=9\,W\]
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