A) 4 min.
B) 4.5 min.
C) 1.5 min.
D) 2 min.
Correct Answer: C
Solution :
\[d=h\cot {{30}^{o}}-h\cot {{60}^{o}}\text{ and time }=\]3 min. \[\therefore \] Speed = \[\frac{h(\cot {{30}^{o}}-\cot {{60}^{o}})}{3}\] per minute It will travel distance \[h\cot {{60}^{o}}\] in \[\frac{h\cot {{60}^{o}}\times 3}{h(\cot {{30}^{o}}-\cot {{60}^{o}})}\] = 1.5 minute.You need to login to perform this action.
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