A) \[\sin \,\,\alpha \,\,\sin \,\,\beta \]
B) \[\cos \,\,\alpha \,\,\cos \,\,\beta \]
C) \[\sin \,\,\alpha \,\,\cos \,\,\beta \]
D) \[\cos \,\,\alpha \,\,\sin \,\,\beta \]
Correct Answer: D
Solution :
\[H=d\tan \beta \] and \[H-h=d\tan \alpha \] \[\Rightarrow \] \[\frac{60}{60-h}=\frac{\tan \beta }{\tan \alpha }\] \[\Rightarrow \] \[-h=\frac{60\tan \alpha -60\tan \beta }{\tan \beta }\] \[\Rightarrow \] \[h=\frac{60\sin (\beta -\alpha )}{\cos \alpha \cos \beta \frac{\sin \beta }{\cos \beta }}\] \[\Rightarrow \] \[x=\cos \alpha \sin \beta \].You need to login to perform this action.
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