A) \[\frac{2.05\,\,\sin \,\,{{38}^{o}}}{\sin \,{{42}^{o}}}\]
B) \[\frac{2.05\,\,\sin \,\,{{42}^{o}}}{\sin \,{{38}^{o}}}\]
C) \[\frac{2.05\,\,\cos \,\,{{38}^{o}}}{\cos \,\,{{42}^{o}}}\]
D) None of these
Correct Answer: A
Solution :
\[\frac{\sin {{38}^{o}}}{l}=\frac{\sin (SPO)}{2.05}\] = \[\frac{\sin ({{180}^{o}}-{{38}^{o}}-{{90}^{o}}-{{10}^{o}})}{2.05}\Rightarrow l=\frac{2.05\sin {{38}^{o}}}{\sin {{42}^{o}}}\].You need to login to perform this action.
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