A) \[2500\,\sqrt{3}\,metres\]
B) 2500 metres
C) \[500\,\sqrt{3}\,metres\]
D) None of these
Correct Answer: A
Solution :
\[(H-h)\cot {{15}^{o}}=(H+h)\cot {{45}^{o}}\] or \[H=\frac{h\,(\cot {{15}^{o}}+1)}{(\cot {{15}^{o}}-1)}\] Since \[h=2500\] and substitute \[\cot {{15}^{o}}=2+\sqrt{3}\],we get, \[H=2500\,\sqrt{3}\].You need to login to perform this action.
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