A) \[\frac{\tan \alpha \,.\,\tan \beta }{\cot \alpha +\cot \beta }\]
B) \[\frac{\tan \alpha +\tan \beta }{\tan \alpha \,.\,\tan \beta }\]
C) \[\frac{\cot \alpha +\cot \beta }{\tan \alpha \,.\,\tan \beta }\]
D) \[\frac{\tan \alpha \,.\,\tan \,\beta }{\tan \alpha +\tan \beta }\]
Correct Answer: D
Solution :
\[{{d}_{1}}=h\cot \alpha \] and \[{{d}_{2}}=h\cot \beta \] \[{{d}_{1}}+{{d}_{2}}=1\] mile = \[h(\cot \alpha +\cot \beta )\] \[\Rightarrow \] \[h=\frac{1}{(\cot \alpha +\cot \beta )}=\frac{\tan \alpha .\tan \beta }{\tan \alpha +\tan \beta }\].You need to login to perform this action.
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