2. Questions Bank
  3. JEE Main & Advanced
  4. Physics

JEE Main & Advanced Physics Question Bank Human Eye and Lens Camera

  • question_answer
    The far point of a myopia eye is at 40 cm. For removing this defect, the power of lens required will be [MP PMT 1987]

    A)            40 D                                         

    B)            ? 4 D

    C)             ? 2.5 D                                   

    D)    0.25 D

    Correct Answer: C

    Solution :

                       For myopic eye f = ? (defected far point)            \[\Rightarrow f=-\,40\,cm\]  Þ \[P=\frac{100}{-40}=-\,2.5\,D\]


You need to login to perform this action.
You will be redirected in 3 sec spinner