A) + 2.0 D
B) ? 1.0 D
C) + 1.0 D
D) ? 0.5 D
Correct Answer: D
Solution :
\[P=\frac{1}{f}=\frac{1}{-(defected\ far\ point)}=-\frac{1}{2}\]\[=-\,0.5\,D\]
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