A) Nearsighted, 50 cm
B) Farsighted, 50 cm
C) Nearsighted, 250 cm
D) Astigmatism, 50 cm
Correct Answer: A
Solution :
The defect is myopia (nearsightness) As we know for myopic person f = ? (defected far point) Þ Defected far point = ? f = ?\[\frac{1}{P}=-\frac{1}{(\,-2)}=0.5\,m\] = 50 cmYou need to login to perform this action.
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