A) 30%
B) 6%
C) 3%
D) 10%
Correct Answer: B
Solution :
\[\because \] 22.4 litre \[{{O}_{2}}\] at N.T.P. obtained by 68 gm of \[{{H}_{2}}{{O}_{2}}\] \ 1 litre \[{{O}_{2}}\]at N.T.P. obtained by\[\frac{68}{22.4}\]gm of \[{{H}_{2}}{{O}_{2}}\] \ 20 litre \[{{O}_{2}}\] at N.T.P. obtained by \[\frac{68}{22.4}\times 20\]gm of \[{{H}_{2}}{{O}_{2}}=60.71\,gm\] of \[{{H}_{2}}{{O}_{2}}\] \ 1000 ml \[{{O}_{2}}\] at N.T.P. obtained by = 60.71 gm of \[{{H}_{2}}{{O}_{2}}\] \ 100 ml \[{{O}_{2}}\] at N.T.P. obtained by \[=\frac{60.71}{1000}\times 100=6.71%\]
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