A) \[{{O}_{3}}\]
B) \[KI/HCl\]
C) PbS
D) \[N{{a}_{2}}S{{O}_{3}}\]
Correct Answer: A
Solution :
\[{{H}_{2}}{{O}_{2}}\] reduces \[{{O}_{3}}\] to \[{{O}_{2}}\] \[{{O}_{3}}+{{H}_{2}}{{O}_{2}}\to {{H}_{2}}O+2{{O}_{2}}\]
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