A) Halogen
B) Alkali metals
C) Chalcogens
D) Alkaline earth metals
Correct Answer: A
Solution :
\[\underset{1{{s}^{1}}}{\mathop{H}}\,+{{e}^{-}}\to \underset{1{{s}^{2}}\text{ or }{{[He]}^{2}}}{\mathop{{{H}^{-}}}}\,\] \[\underset{{{[He]}^{2}}2{{s}^{2}}2{{p}^{5}}}{\mathop{F+{{e}^{-}}}}\,\to \underset{{{[He]}^{2}}2{{s}^{2}}2{{p}^{6}}\text{ or }{{[Ne]}^{10}}}{\mathop{{{F}^{-}}}}\,\]
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