A) 0.224 litre
B) 0.448 litre
C) 22.4 litre
D) 2.24 litre
Correct Answer: B
Solution :
No. of moles of \[C{{O}_{2}}\]present in 200 ml solution = molarity ´ Volume (in lt.) \[=0.1\times \frac{200}{1000}=.02\] Volume of 0.02 mole of \[C{{O}_{2}}=22.4\times .02lt.\]\[=0.448lit.\]You need to login to perform this action.
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