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JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Increasing and Decreasing Function

  • question_answer
    The function \[\frac{x-2}{x+1},(x\ne -1)\]is increasing on the interval

    A)            \[(-\infty ,\,\,\,0]\]

    B)            [0, \[\infty \])

    C)            R

    D)            None of these

    Correct Answer: C

    Solution :

               Since \[f'(x)=\frac{3}{{{(x+1)}^{2}}}\]is greater than '0' in interval \[(-\infty ,\,\infty ),\] therefore \[f(x)=\frac{x-2}{x+1}\] is increasing in interval \[(-\infty ,\,\infty )\] or R.


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