A) \[{{\eta }_{0}}\,=\,{{h}_{mech}}\,\times \,{{\eta }_{hyd}}\]
B) \[{{\eta }_{0}}\,=\,{{h}_{mech}}\,/\,{{\eta }_{hyd}}\]
C) \[{{\eta }_{0}}\,=\,{{\eta }_{hyd}}\,/\,{{\eta }_{mech}}\]
D) \[{{\eta }_{0}}\,=\,{{\eta }_{mech}}\,-\,{{\eta }_{hyd}}\]
Correct Answer: A
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