A) 6.5 kW
B) 8.7 kW
C) 9.8 kW
D) 10.9 kW
Correct Answer: C
Solution :
\[P\alpha {{N}^{3}}.{{P}_{2}}={{P}_{1}}{{\left( \frac{{{N}_{2}}}{{{N}_{1}}} \right)}^{3}}=5{{\left( \frac{1500}{1200} \right)}^{3}}\] = 9.8 kWYou need to login to perform this action.
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