A) \[\frac{24}{13}+\frac{10}{13}i\]
B) \[\frac{24}{13}-\frac{10}{13}i\]
C) \[\frac{10}{13}+\frac{24}{13}i\]
D) \[\frac{10}{13}-\frac{24}{13}i\]
Correct Answer: D
Solution :
\[\frac{1-2i}{2+i}+\frac{4-i}{3+2i}=\frac{(1-2i)(3+2i)+(4-i)(2+i)}{(2+i)(3+2i)}\] \[=\frac{50-120i}{65}=\frac{10}{13}-\frac{24}{13}i\].You need to login to perform this action.
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