A) \[\log ({{x}^{2}}+4x+13)+c\]
B) \[\frac{1}{3}{{\tan }^{-1}}\left( \frac{x+2}{3} \right)+c\]
C) \[\log (2x+4)+c\]
D) \[\frac{2x+4}{{{({{x}^{2}}+4x+13)}^{2}}}+c\]
Correct Answer: B
Solution :
\[\int{\frac{dx}{{{x}^{2}}+4x+13}=\int{\frac{dx}{{{(x+2)}^{2}}+9}=\frac{1}{3}{{\tan }^{-1}}\frac{(x+2)}{3}+c}}\].You need to login to perform this action.
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