A) \[{{\sin }^{-1}}(x+1)+c\]
B) \[{{\sinh }^{-1}}(x+1)+c\]
C) \[{{\tanh }^{-1}}(x+1)+c\]
D) \[{{\tan }^{-1}}(x+1)+c\]
Correct Answer: D
Solution :
\[\int_{{}}^{{}}{\frac{dx}{{{x}^{2}}+2x+2}=\int_{{}}^{{}}{\frac{dx}{{{(x+1)}^{2}}+1}={{\tan }^{-1}}(x+1)+c}}\].You need to login to perform this action.
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