A) 9 : 1
B) 1 : 9
C) 4 : 1
D) 1 : 4
Correct Answer: A
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\frac{{{a}_{1}}}{{{a}_{2}}}+1}{\frac{{{a}_{1}}}{{{a}_{2}}}-1} \right)}^{2}}={{\left( \frac{2+1}{2-1} \right)}^{2}}=9/1\]
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