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JEE Main & Advanced Physics Wave Mechanics Question Bank Interference and Superposition of Waves

  • question_answer
    When two sound waves with a phase difference of \[\pi /2\], and each having amplitude A and frequency \[\omega \], are superimposed on each other, then the maximum amplitude and frequency of resultant wave is                 [MP PMT 1989]

    A)            \[\frac{A}{\sqrt{2}}:\frac{\omega }{2}\]                      

    B)            \[\frac{A}{\sqrt{2}}:\omega \]

    C)            \[\sqrt{2}\,A:\frac{\omega }{2}\]                                   

    D)            \[\sqrt{2}\,A:\omega \]

    Correct Answer: D

    Solution :

               \[{{A}_{\max }}=\sqrt{{{A}^{2}}+{{A}^{2}}}=A\sqrt{2},\]frequency will remain same i.e. w.


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