A) 16 : 18
B) 18 : 16
C) 49 : 1
D) 1 : 49
Correct Answer: C
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\frac{{{a}_{1}}}{{{a}_{2}}}+1}{\frac{{{a}_{1}}}{{{a}_{2}}}-1} \right)}^{2}}={{\left( \frac{\frac{4}{3}+1}{\frac{4}{3}-1} \right)}^{2}}=\frac{49}{1}\]
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