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JEE Main & Advanced Physics Wave Mechanics Question Bank Interference and Superposition of Waves

  • question_answer
    Equation of motion in the same direction is given by \[{{y}_{1}}=A\sin (\omega t-kx)\], \[{{y}_{2}}=A\sin (\omega t-kx-\theta )\]. The amplitude of the medium particle will be                         [BHU 2003]

    A)            \[2A\cos \frac{\theta }{2}\]   

    B)            \[2A\cos \theta \]

    C)            \[\sqrt{2}A\cos \frac{\theta }{2}\]                                 

    D)            \[1.2f,\ 1.2\lambda \]

    Correct Answer: A

    Solution :

               The resultant amplitude is given by                    \[{{A}_{R}}=\sqrt{{{A}^{2}}+{{A}^{2}}+2AA\cos \theta }=\sqrt{2{{A}^{2}}(1+\cos \theta )}\]            \[=2A\cos \theta /2\]        \[{n}'=2n\]


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