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JEE Main & Advanced Physics Wave Mechanics Question Bank Interference and Superposition of Waves

  • question_answer
    Two sources of sound A and B produces the wave of 350 Hz, they vibrate in the same phase. The particle P is vibrating under the influence of these two waves, if the amplitudes at the point P produced by the two waves is 0.3 mm and 0.4 mm, then the resultant amplitude of the point P will be when AP ? BP = 25 cm and the velocity of sound is 350 m/sec 

    A)            0.7 mm                                   

    B)            0.1 mm

    C)            0.2 mm                                   

    D)            0.5 mm

    Correct Answer: D

    Solution :

               \[\lambda =\frac{v}{n}=\frac{350}{350}=1\,m\]=100 cm Also path difference \[(\Delta x)\] between the waves at the point of observation is \[AP-BP=25cm\].   Hence Þ \[\Delta \varphi =\frac{2\pi }{\lambda }(\Delta x)=\frac{2\pi }{1}\times \left( \frac{25}{100} \right)=\frac{\pi }{2}\] Þ \[A=\sqrt{{{({{a}_{1}})}^{2}}+{{({{a}_{2}})}^{2}}}\]\[=\]\[\sqrt{{{(0.3)}^{2}}+{{(0.4)}^{2}}}\]= 0.5 \[mm\]


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