A) 200%
B) 100%
C) 66.666%
D) 33.333%
Correct Answer: C
Solution :
Propulsive efficiency, \[{{\eta }_{p}}=\frac{2\,{{v}_{f}}}{{{v}_{g}}+{{v}_{f}}}=\frac{2\times 1350}{2700+1350}=\frac{2}{3}=66.666%\]You need to login to perform this action.
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