A) 0
B) 1
C) \[\frac{1}{2}\]
D) \[\frac{\sqrt{3}}{2}\]
Correct Answer: A
Solution :
\[\text{1}0\text{4}=\text{16}\times \text{6}+\text{8}\] \[16=8\times 2+0\] [ Since\[\text{256}=\text{8}\times \text{32}+0\]] \[3465={{3}^{2}}\times 5\times 7\times 11\]\[\text{546}0=\text{22}\times \text{3}\times \text{5}\times \text{7}\times \text{l3}\]
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