question_answer

If \[\mathbf{sin 2x=}\frac{\mathbf{2tan 30{}^\circ }}{\mathbf{1+ ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{ 30}}\] , then the  value of \[\frac{\mathbf{1}-\mathbf{ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}{\mathbf{1+ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}\]is equal to____ (where\[0{}^\circ <x<90{}^\circ \])

A)  Sin x    

B)  Cos 3x       

C)  0                                                                    

D)  1

E) None of these