A) \[\frac{-3}{2}\]
B) \[\frac{3}{2}\]
C) \[\frac{2}{3}\]
D) \[\frac{-2}{3}\]
Correct Answer: B
Solution :
\[\sin \theta =\cos \theta \Rightarrow \frac{\sin \theta }{\cos \theta }=1\Rightarrow \tan \theta =1\]and \[\tan \theta =\tan {{45}^{o}}\Rightarrow \theta ={{45}^{o}}\] \[\therefore \]\[2{{\tan }^{2}}\theta +{{\sin }^{2}}\theta -1=2{{\tan }^{2}}{{45}^{o}}+{{\sin }^{2}}{{45}^{o}}-1\] \[=2{{(1)}^{2}}+{{\left( \frac{1}{\sqrt{2}} \right)}^{2}}-1=2+\frac{1}{2}-1=\frac{3}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
